如何让开关触发，使0，1针脚给其他设备发送串口命令
各位社区的大神们好，我是小白一个，没什么编程基础。有个需求搜了搜还不知道怎么做。详见图片：Arduino通过0，1针脚用串口线和摄像机串口连接，通过开关点按触发Arduino开发板给摄像机发控制码，控制码是16进制数组，如：AA 64 02 01 02
按一次开关，触发给摄像机发送AA 64 02 01 02，第二次按发送AA 64 02 01 03，再次循环往复···
求问，如何编写代码实现，感谢。
本帖最后由 i7456 于 2020-4-15 13:16 编辑
int code1[] ={0xAA, 0x64, 0x02, 0x01, 0x02};
int code2[] ={0xAA, 0x64, 0x02, 0x01, 0x03};
// this constant won't change:
const intbuttonPin = 2; // the pin that the pushbutton is attached to
const int ledPin = 13; // the pin that the LED is attached to
// Variables will change:
int buttonPushCounter = 0; // counter for the number of button presses
int buttonState = 0; // current state of the button
int lastButtonState = 0; // previous state of the button
void setup() {
// initialize the button pin as a input:
pinMode(buttonPin, INPUT);
// initialize the LED as an output:
pinMode(ledPin, OUTPUT);
// initialize serial communication:
Serial.begin(9600);
}
void loop() {
// read the pushbutton input pin:
buttonState = digitalRead(buttonPin);
// compare the buttonState to its previous state
if (buttonState != lastButtonState) {
// if the state has changed, increment the counter
if (buttonState == HIGH) {
// if the current state is HIGH then the button went from off to on:
buttonPushCounter++;
if (buttonPushCounter % 2 == 0) {
digitalWrite(ledPin, HIGH);
for(int i = 0; i < 5; i++)
Serial.print(code1);
} else {
digitalWrite(ledPin, LOW);
for(int i = 0; i < 5; i++)
Serial.print(code2);
}
}
// Delay a little bit to avoid bouncing
delay(50);
}
// save the current state as the last state, for next time through the loop
lastButtonState = buttonState;
}
i7456 发表于 2020-4-15 13:13
int code1[] ={0xAA, 0x64, 0x02, 0x01, 0x02};
int code2[] ={0xAA, 0x64, 0x02, 0x01, 0x03};
感谢大神回复，我找个板子接好刷进去试下。代码根据注释能看懂个八成左右，谢谢。
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