关于串口输出格式的小问题

１９００

传感器的三个模拟信号输入Mango2的A0，A1，A2端，串口输出数字信号，想让一条数据的三个值在同一行显示
一下是我的代码
void loop() {
  // read the input on analog pin 0:
  
  int sensorValue0 = analogRead(A0);
  int sensorValue1 = analogRead(A1);
  int sensorValue2 = analogRead(A2);
  // print out the value you read:
   a = ++a;
  Serial.print(a);
  Serial.print(".");
  Serial.println(sensorValue0);
  Serial.print(".");
  Serial.println(sensorValue1);
  Serial.print(".");
  Serial.println(sensorValue2);
  delay(200);        // delay in between reads for stability
}
用串口监视器查看输出，看到自动换行了（如下），请问怎样让一条数据三个值在一行里面显示？
12.0
.0
.62
13.188
.0
.592
14.478
.28
.273
15.468

zoologist

将值输出到一个 string 中然后一起输出试试看
     char buf[32];               //Output buffer
      snprintf(buf, sizeof(buf), "%d %d" value1,value2);      
      lcd.print(buf);

pathletboy

1. void loop() {
   
2.   // read the input on analog pin 0:
   
3.   
   
4.   int sensorValue0 = analogRead(A0);
   
5.   int sensorValue1 = analogRead(A1);
   
6.   int sensorValue2 = analogRead(A2);
   
7.   // print out the value you read:
   
8.    a = ++a;
   
9.   Serial.print(a);
   
10.   Serial.print(".");
    
11.   Serial.print(sensorValue0);
    
12.   Serial.print(".");
    
13.   Serial.print(sensorValue1);
    
14.   Serial.print(".");
    
15.   Serial.println(sensorValue2);
    
16.   delay(200);        // delay in between reads for stability
    
17. }

复制代码

１９００

pathletboy 发表于 2013-12-8 23:18
void loop() {
  // read the input on analog pin 0:
  

原来print是接着输出，println是换行输出，多谢指教！