看了别人的程序,却不能让步进电机正常运转,经过查找原因,发现是接线问题,根据两相四线步进电机的四拍工作方式,其各相通电顺序为 A-AB-B-BA’-A’-A’B’-B’-B’A)。接线方式别的资料都有,可以去找,我是分别接到8、9(一相),10、11(另一相),这样程序需要进行适当修改。当然,我仅仅是为了测试步进电机好坏,可以看到速度的变化。如果实际运行,还要完善程序。程序中(digitalWrite(Pin2, LOW); digitalWrite(Pin3, HIGH);)定义为A;( digitalWrite(Pin0, LOW); digitalWrite(Pin1, HIGH);)定义为B,A’和B’相反就可以。程序如下(程序修改于网上找到的程序):
int Pin0 = 8;
int Pin1 = 9;
int Pin2 = 10;
int Pin3 = 11;
int _step =0 ;
boolean dir = false;//正反转
int stepperSpeed = 1;//电机转速,1ms一步
void setup()
{
pinMode(Pin0, OUTPUT);
pinMode(Pin1, OUTPUT);
pinMode(Pin2, OUTPUT);
pinMode(Pin3, OUTPUT);
}
void loop()
{
switch(_step){
case 0:
stepperSpeed++;
digitalWrite(Pin0, LOW);
digitalWrite(Pin1, LOW);
digitalWrite(Pin2, LOW);
digitalWrite(Pin3, HIGH);//32A
break;
case 1:
digitalWrite(Pin0, LOW);
digitalWrite(Pin1, HIGH);//10B
digitalWrite(Pin2, LOW);
digitalWrite(Pin3, HIGH);
break;
case 2:
digitalWrite(Pin0, LOW);
digitalWrite(Pin1, HIGH);
digitalWrite(Pin2, LOW);
digitalWrite(Pin3, LOW);
break;
case 3:
digitalWrite(Pin0, LOW);
digitalWrite(Pin1, HIGH);
digitalWrite(Pin2, HIGH);
digitalWrite(Pin3, LOW);
break;
case 4:
digitalWrite(Pin0, LOW);
digitalWrite(Pin1, LOW);
digitalWrite(Pin2, HIGH);
digitalWrite(Pin3, LOW);
break;
case 5:
digitalWrite(Pin0, HIGH);
digitalWrite(Pin1, LOW);
digitalWrite(Pin2, HIGH);
digitalWrite(Pin3, LOW);
break;
case 6:
digitalWrite(Pin0, HIGH);
digitalWrite(Pin1, LOW);
digitalWrite(Pin2, LOW);
digitalWrite(Pin3, LOW);
break;
case 7:
digitalWrite(Pin0, HIGH);
digitalWrite(Pin1, LOW);
digitalWrite(Pin2, LOW);
digitalWrite(Pin3, HIGH);
break;
default:
digitalWrite(Pin0, LOW);
digitalWrite(Pin1, LOW);
digitalWrite(Pin2, LOW);
digitalWrite(Pin3, LOW);
break;
}
if(dir){
_step++;
}else{
_step--;
}
if(_step>7){
_step=0;
}
if(_step<0){
_step=7;
}
delay(stepperSpeed);
}
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